Obtain the roots of the following quadratic e | vedclass

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(C) The given quadratic equation is $9x^{2} + 7x - 2 = 0$.Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = 9$,$b = 7$,and $c =

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$\frac{2}{9}, -1$

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(C) The given quadratic equation is $9x^{2} + 7x - 2 = 0$.Comparing this with the standard form $ax^{2} + bx + c = 0$,we get $a = 9$,$b = 7$,and $c = -2$.The quadratic formula is given by $x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$.First,calculate the discriminant $D = b^{2} - 4ac = (7)^{2} - 4(9)(-2) = 49 + 72 = 121$.Now,substitute the values into the formula:$x = \frac{-7 \pm \sqrt{121}}{2(9)}$$x = \frac{-7 \pm 11}{18}$Case $1$: $x = \frac{-7 + 11}{18} = \frac{4}{18} = \frac{2}{9}$.Case $2$: $x = \frac{-7 - 11}{18} = \frac{-18}{18} = -1$.Thus,the roots of the equation are $\frac{2}{9}$ and $-1$.

Obtain the roots of the following quadratic equation by using the quadratic formula: $9x^{2} + 7x - 2 = 0$.

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